2x^2+26x=-80

Solution for 2x^2+26x=-80 equation:

2x^2+26x=-80

We move all terms to the left:

2x^2+26x-(-80)=0

We add all the numbers together, and all the variables

2x^2+26x+80=0

a = 2; b = 26; c = +80;
Δ = b2-4ac
Δ = 262-4·2·80
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-6}{2*2}=\frac{-32}{4}
=-8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+6}{2*2}=\frac{-20}{4}
=-5
$